17+3z+13-z=4z+5+2z-7

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Solution for 17+3z+13-z=4z+5+2z-7 equation: 



17+3z+13-z=4z+5+2z-7

We move all terms to the left:

17+3z+13-z-(4z+5+2z-7)=0

We add all the numbers together, and all the variables

3z-z-(6z-2)+17+13=0

We add all the numbers together, and all the variables

2z-(6z-2)+30=0

We get rid of parentheses

2z-6z+2+30=0

We add all the numbers together, and all the variables

-4z+32=0

We move all terms containing z to the left, all other terms to the right

-4z=-32

z=-32/-4

z=+8

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