1/4z+12=15

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Solution for 1/4z+12=15 equation: 



1/4z+12=15

We move all terms to the left:

1/4z+12-(15)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

1/4z-3=0

We multiply all the terms by the denominator


-3*4z+1=0

Wy multiply elements

-12z+1=0

We move all terms containing z to the left, all other terms to the right

-12z=-1

z=-1/-12

z=1/12

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