540=(180-(2z+45))+333

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Solution for 540=(180-(2z+45))+333 equation: 



540=(180-(2z+45))+333

We move all terms to the left:

540-((180-(2z+45))+333)=0



We calculate terms in parentheses: -((180-(2z+45))+333), so:

(180-(2z+45))+333



We calculate terms in parentheses: +(180-(2z+45)), so:

180-(2z+45)

determiningTheFunctionDomain
-(2z+45)+180

We get rid of parentheses

-2z-45+180

We add all the numbers together, and all the variables

-2z+135

Back to the equation:

+(-2z+135)



We get rid of parentheses

-2z+135+333

We add all the numbers together, and all the variables

-2z+468

Back to the equation:

-(-2z+468)



We get rid of parentheses

2z-468+540=0

We add all the numbers together, and all the variables

2z+72=0

We move all terms containing z to the left, all other terms to the right

2z=-72

z=-72/2

z=-36

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