-2(-4+b)=2-2(b-3)

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Solution for -2(-4+b)=2-2(b-3) equation: 



-2(-4+b)=2-2(b-3)

We move all terms to the left:

-2(-4+b)-(2-2(b-3))=0

We add all the numbers together, and all the variables

-2(b-4)-(2-2(b-3))=0

We multiply parentheses

-2b-(2-2(b-3))+8=0



We calculate terms in parentheses: -(2-2(b-3)), so:

2-2(b-3)

determiningTheFunctionDomain
-2(b-3)+2

We multiply parentheses

-2b+6+2

We add all the numbers together, and all the variables

-2b+8

Back to the equation:

-(-2b+8)



We get rid of parentheses

-2b+2b-8+8=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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