540=((2z+45)-180)+333

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Solution for 540=((2z+45)-180)+333 equation: 



540=((2z+45)-180)+333

We move all terms to the left:

540-(((2z+45)-180)+333)=0



We calculate terms in parentheses: -(((2z+45)-180)+333), so:

((2z+45)-180)+333



We calculate terms in parentheses: +((2z+45)-180), so:

(2z+45)-180

We get rid of parentheses

2z+45-180

We add all the numbers together, and all the variables

2z-135

Back to the equation:

+(2z-135)



We get rid of parentheses

2z-135+333

We add all the numbers together, and all the variables

2z+198

Back to the equation:

-(2z+198)



We get rid of parentheses

-2z-198+540=0

We add all the numbers together, and all the variables

-2z+342=0

We move all terms containing z to the left, all other terms to the right

-2z=-342

z=-342/-2

z=+171

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