51z+48=9z+6(8+7z)

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Solution for 51z+48=9z+6(8+7z) equation: 



51z+48=9z+6(8+7z)

We move all terms to the left:

51z+48-(9z+6(8+7z))=0

We add all the numbers together, and all the variables

51z-(9z+6(7z+8))+48=0



We calculate terms in parentheses: -(9z+6(7z+8)), so:

9z+6(7z+8)

We multiply parentheses

9z+42z+48

We add all the numbers together, and all the variables

51z+48

Back to the equation:

-(51z+48)



We get rid of parentheses

51z-51z-48+48=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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