6(x+1)+2=3(x/5x)+1

Solution for 6(x+1)+2=3(x/5x)+1 equation:

6(x+1)+2=3(x/5x)+1

We move all terms to the left:

6(x+1)+2-(3(x/5x)+1)=0


Domain of the equation: 5x)+1)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

6(x+1)-(3(+x/5x)+1)+2=0

We multiply parentheses

6x-(3(+x/5x)+1)+6+2=0

We multiply all the terms by the denominator


6x*5x)+1)-(3(+x+6*5x)+1)+2*5x)+1)=0

We add all the numbers together, and all the variables

x+6x*5x)+1)-(3(+6*5x)+1)+2*5x)+1)=0

Wy multiply elements

30x^2+150x^2+x=0

We add all the numbers together, and all the variables

180x^2+x=0

a = 180; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·180·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*180}=\frac{-2}{360}
=-1/180
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*180}=\frac{0}{360}
=0
$