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4(x-5)-3(x+5)=35-(x+8)5
We move all terms to the left:
4(x-5)-3(x+5)-(35-(x+8)5)=0
We multiply parentheses
4x-3x-(35-(x+8)5)-20-15=0
We calculate terms in parentheses: -(35-(x+8)5), so:We add all the numbers together, and all the variables
35-(x+8)5
determiningTheFunctionDomain -(x+8)5+35
We multiply parentheses
-5x-40+35
We add all the numbers together, and all the variables
-5x-5
Back to the equation:
-(-5x-5)
x-(-5x-5)-35=0
We get rid of parentheses
x+5x+5-35=0
We add all the numbers together, and all the variables
6x-30=0
We move all terms containing x to the left, all other terms to the right
6x=30
x=30/6
x=5
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