50z=-50-80(1-z)

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Solution for 50z=-50-80(1-z) equation: 



50z=-50-80(1-z)

We move all terms to the left:

50z-(-50-80(1-z))=0

We add all the numbers together, and all the variables

50z-(-50-80(-1z+1))=0



We calculate terms in parentheses: -(-50-80(-1z+1)), so:

-50-80(-1z+1)

determiningTheFunctionDomain
-80(-1z+1)-50

We multiply parentheses

80z-80-50

We add all the numbers together, and all the variables

80z-130

Back to the equation:

-(80z-130)



We get rid of parentheses

50z-80z+130=0

We add all the numbers together, and all the variables

-30z+130=0

We move all terms containing z to the left, all other terms to the right

-30z=-130

z=-130/-30

z=4+1/3

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