5/9z=35

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Solution for 5/9z=35 equation: 



5/9z=35

We move all terms to the left:

5/9z-(35)=0



Domain of the equation: 9z!=0

z!=0/9

z!=0

z∈R



We multiply all the terms by the denominator


-35*9z+5=0

Wy multiply elements

-315z+5=0

We move all terms containing z to the left, all other terms to the right

-315z=-5

z=-5/-315

z=1/63

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