(4+20)4=x2

Solution for (4+20)4=x2 equation:

(4+20)4=x2

We move all terms to the left:

(4+20)4-(x2)=0

We add all the numbers together, and all the variables

-x2+244=0

We add all the numbers together, and all the variables

-1x^2+244=0

a = -1; b = 0; c = +244;
Δ = b2-4ac
Δ = 02-4·(-1)·244
Δ = 976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{976}=\sqrt{16*61}=\sqrt{16}*\sqrt{61}=4\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{61}}{2*-1}=\frac{0-4\sqrt{61}}{-2}
=-\frac{4\sqrt{61}}{-2}
=-\frac{2\sqrt{61}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{61}}{2*-1}=\frac{0+4\sqrt{61}}{-2}
=\frac{4\sqrt{61}}{-2}
=\frac{2\sqrt{61}}{-1}
$