34+(3x-68)=x

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Solution for 34+(3x-68)=x equation: 



34+(3x-68)=x

We move all terms to the left:

34+(3x-68)-(x)=0

We add all the numbers together, and all the variables

-1x+(3x-68)+34=0

We get rid of parentheses

-1x+3x-68+34=0

We add all the numbers together, and all the variables

2x-34=0

We move all terms containing x to the left, all other terms to the right

2x=34

x=34/2

x=17

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