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5/6y+1=1/2y+1
We move all terms to the left:
5/6y+1-(1/2y+1)=0
Domain of the equation: 6y!=0
y!=0/6
y!=0
y∈R
Domain of the equation: 2y+1)!=0We get rid of parentheses
y∈R
5/6y-1/2y-1+1=0
We calculate fractions
10y/12y^2+(-6y)/12y^2-1+1=0
We add all the numbers together, and all the variables
10y/12y^2+(-6y)/12y^2=0
We multiply all the terms by the denominator
10y+(-6y)=0
We get rid of parentheses
10y-6y=0
We add all the numbers together, and all the variables
4y=0
y=0/4
y=0
Równanie nie ma rozwiązania
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