5/6(7x-9)=2/3(4x+3)

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Solution for 5/6(7x-9)=2/3(4x+3) equation: 



5/6(7x-9)=2/3(4x+3)

We move all terms to the left:

5/6(7x-9)-(2/3(4x+3))=0



Domain of the equation: 6(7x-9)!=0

x∈R





Domain of the equation: 3(4x+3))!=0

x∈R



We calculate fractions


(15x4/(6(7x-9)*3(4x+3)))+(-12x7/(6(7x-9)*3(4x+3)))=0



We calculate terms in parentheses: +(15x4/(6(7x-9)*3(4x+3))), so:

15x4/(6(7x-9)*3(4x+3))

We multiply all the terms by the denominator


15x4

We add all the numbers together, and all the variables

15x^4

We do not support expression: x^4

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