3(2x+2)=4(3x-2)

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Solution for 3(2x+2)=4(3x-2) equation: 



3(2x+2)=4(3x-2)

We move all terms to the left:

3(2x+2)-(4(3x-2))=0

We multiply parentheses

6x-(4(3x-2))+6=0



We calculate terms in parentheses: -(4(3x-2)), so:

4(3x-2)

We multiply parentheses

12x-8

Back to the equation:

-(12x-8)



We get rid of parentheses

6x-12x+8+6=0

We add all the numbers together, and all the variables

-6x+14=0

We move all terms containing x to the left, all other terms to the right

-6x=-14

x=-14/-6

x=2+1/3

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