6(3y-5)=7(3y-2)

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Solution for 6(3y-5)=7(3y-2) equation: 



6(3y-5)=7(3y-2)

We move all terms to the left:

6(3y-5)-(7(3y-2))=0

We multiply parentheses

18y-(7(3y-2))-30=0



We calculate terms in parentheses: -(7(3y-2)), so:

7(3y-2)

We multiply parentheses

21y-14

Back to the equation:

-(21y-14)



We get rid of parentheses

18y-21y+14-30=0

We add all the numbers together, and all the variables

-3y-16=0

We move all terms containing y to the left, all other terms to the right

-3y=16

y=16/-3

y=-5+1/3

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