5-3q=4-(2/3)(4.5q-1.5)

Solution for 5-3q=4-(2/3)(4.5q-1.5) equation:

5-3q=4-(2/3)(4.5q-1.5)

We move all terms to the left:

5-3q-(4-(2/3)(4.5q-1.5))=0


Domain of the equation: 3)(4.5q-1.5))!=0

q∈R


We add all the numbers together, and all the variables

-3q-(4-(+2/3)(4.5q-1.5))+5=0

We multiply parentheses ..

-(4-(+8q^2+2/3*-1.5))-3q+5=0

We multiply all the terms by the denominator


-(4-(+8q^2+2-3q*3*-1.5))+5*3*-1.5))=0


We calculate terms in parentheses: -(4-(+8q^2+2-3q*3*-1.5)), so:

4-(+8q^2+2-3q*3*-1.5)

determiningTheFunctionDomain
-(+8q^2+2-3q*3*-1.5)+4

We get rid of parentheses

-8q^2+3q*3*-2+1.5+4

We add all the numbers together, and all the variables

-8q^2+3q*3*+3.5

Wy multiply elements

-8q^2+9q^2+3.5

We add all the numbers together, and all the variables

q^2+3.5

Back to the equation:

-(q^2+3.5)


We add all the numbers together, and all the variables

-(q^2+3.5)=0

We get rid of parentheses

-q^2-3.5=0

We add all the numbers together, and all the variables

-1q^2-3.5=0

a = -1; b = 0; c = -3.5;
Δ = b2-4ac
Δ = 02-4·(-1)·(-3.5)
Δ = -14
Delta is less than zero, so there is no solution for the equation