3b+5=2(6b-21)

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Solution for 3b+5=2(6b-21) equation: 



3b+5=2(6b-21)

We move all terms to the left:

3b+5-(2(6b-21))=0



We calculate terms in parentheses: -(2(6b-21)), so:

2(6b-21)

We multiply parentheses

12b-42

Back to the equation:

-(12b-42)



We get rid of parentheses

3b-12b+42+5=0

We add all the numbers together, and all the variables

-9b+47=0

We move all terms containing b to the left, all other terms to the right

-9b=-47

b=-47/-9

b=5+2/9

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