5-3=4-(2/3)(4.5q-1.5)

Solution for 5-3=4-(2/3)(4.5q-1.5) equation:

5-3=4-(2/3)(4.5q-1.5)

We move all terms to the left:

5-3-(4-(2/3)(4.5q-1.5))=0


Domain of the equation: 3)(4.5q-1.5))!=0

q∈R


We add all the numbers together, and all the variables

-(4-(+2/3)(4.5q-1.5))+5-3=0

We add all the numbers together, and all the variables

-(4-(+2/3)(4.5q-1.5))+2=0

We multiply parentheses ..

-(4-(+8q^2+2/3*-1.5))+2=0

We multiply all the terms by the denominator


-(4-(+8q^2+2+2*3*-1.5))=0


We calculate terms in parentheses: -(4-(+8q^2+2+2*3*-1.5)), so:

4-(+8q^2+2+2*3*-1.5)

determiningTheFunctionDomain
-(+8q^2+2+2*3*-1.5)+4

We get rid of parentheses

-8q^2-2+1.5+4-2*3*

We add all the numbers together, and all the variables

-8q^2

Back to the equation:

-(-8q^2)


We get rid of parentheses

8q^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{0}{16}=0$