5-3(x+1)=2(x-4)

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Solution for 5-3(x+1)=2(x-4) equation: 



5-3(x+1)=2(x-4)

We move all terms to the left:

5-3(x+1)-(2(x-4))=0

We multiply parentheses

-3x-(2(x-4))-3+5=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

-3x-(2x-8)+2=0

We get rid of parentheses

-3x-2x+8+2=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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