-36=2(-6r+3)+6(r-5)

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Solution for -36=2(-6r+3)+6(r-5) equation: 



-36=2(-6r+3)+6(r-5)

We move all terms to the left:

-36-(2(-6r+3)+6(r-5))=0



We calculate terms in parentheses: -(2(-6r+3)+6(r-5)), so:

2(-6r+3)+6(r-5)

We multiply parentheses

-12r+6r+6-30

We add all the numbers together, and all the variables

-6r-24

Back to the equation:

-(-6r-24)



We get rid of parentheses

6r+24-36=0

We add all the numbers together, and all the variables

6r-12=0

We move all terms containing r to the left, all other terms to the right

6r=12

r=12/6

r=2

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