2(x+2)+4=4(3-x)+10

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Solution for 2(x+2)+4=4(3-x)+10 equation: 



2(x+2)+4=4(3-x)+10

We move all terms to the left:

2(x+2)+4-(4(3-x)+10)=0

We add all the numbers together, and all the variables

2(x+2)-(4(-1x+3)+10)+4=0

We multiply parentheses

2x-(4(-1x+3)+10)+4+4=0



We calculate terms in parentheses: -(4(-1x+3)+10), so:

4(-1x+3)+10

We multiply parentheses

-4x+12+10

We add all the numbers together, and all the variables

-4x+22

Back to the equation:

-(-4x+22)



We add all the numbers together, and all the variables

2x-(-4x+22)+8=0

We get rid of parentheses

2x+4x-22+8=0

We add all the numbers together, and all the variables

6x-14=0

We move all terms containing x to the left, all other terms to the right

6x=14

x=14/6

x=2+1/3

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