25+3(2x-5)=4(x-1)-2

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Solution for 25+3(2x-5)=4(x-1)-2 equation: 



25+3(2x-5)=4(x-1)-2

We move all terms to the left:

25+3(2x-5)-(4(x-1)-2)=0

We multiply parentheses

6x-(4(x-1)-2)-15+25=0



We calculate terms in parentheses: -(4(x-1)-2), so:

4(x-1)-2

We multiply parentheses

4x-4-2

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

6x-(4x-6)+10=0

We get rid of parentheses

6x-4x+6+10=0

We add all the numbers together, and all the variables

2x+16=0

We move all terms containing x to the left, all other terms to the right

2x=-16

x=-16/2

x=-8

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