5-3(2x-3)=-4(x+1)-3+3x

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Solution for 5-3(2x-3)=-4(x+1)-3+3x equation: 



5-3(2x-3)=-4(x+1)-3+3x

We move all terms to the left:

5-3(2x-3)-(-4(x+1)-3+3x)=0

We multiply parentheses

-6x-(-4(x+1)-3+3x)+9+5=0



We calculate terms in parentheses: -(-4(x+1)-3+3x), so:

-4(x+1)-3+3x

determiningTheFunctionDomain
-4(x+1)+3x-3

We add all the numbers together, and all the variables

3x-4(x+1)-3

We multiply parentheses

3x-4x-4-3

We add all the numbers together, and all the variables

-1x-7

Back to the equation:

-(-1x-7)



We add all the numbers together, and all the variables

-6x-(-1x-7)+14=0

We get rid of parentheses

-6x+1x+7+14=0

We add all the numbers together, and all the variables

-5x+21=0

We move all terms containing x to the left, all other terms to the right

-5x=-21

x=-21/-5

x=4+1/5

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