4y+7=2(y+5)+37

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Solution for 4y+7=2(y+5)+37 equation: 



4y+7=2(y+5)+37

We move all terms to the left:

4y+7-(2(y+5)+37)=0



We calculate terms in parentheses: -(2(y+5)+37), so:

2(y+5)+37

We multiply parentheses

2y+10+37

We add all the numbers together, and all the variables

2y+47

Back to the equation:

-(2y+47)



We get rid of parentheses

4y-2y-47+7=0

We add all the numbers together, and all the variables

2y-40=0

We move all terms containing y to the left, all other terms to the right

2y=40

y=40/2

y=20

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