4(k-3)/6=2(k-5)/4

Solution for 4(k-3)/6=2(k-5)/4 equation:

4(k-3)/6=2(k-5)/4

We move all terms to the left:

4(k-3)/6-(2(k-5)/4)=0

We calculate fractions


4k/()+(-(2(k-5)*6)/()=0


We calculate terms in parentheses: +(-(2(k-5)*6)/(), so:

-(2(k-5)*6)/(

We multiply all the terms by the denominator


-(2(k-5)*6)


We calculate terms in parentheses: -(2(k-5)*6), so:

2(k-5)*6

We multiply parentheses

12k-60

Back to the equation:

-(12k-60)


We get rid of parentheses

-12k+60

Back to the equation:

+(-12k+60)


We get rid of parentheses

4k/()-12k+60=0

We multiply all the terms by the denominator


4k-12k*()+60*()=0

We add all the numbers together, and all the variables

4k-12k*()=0