4(a-3)=7(a-1)-5(a+2)+3

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Solution for 4(a-3)=7(a-1)-5(a+2)+3 equation: 



4(a-3)=7(a-1)-5(a+2)+3

We move all terms to the left:

4(a-3)-(7(a-1)-5(a+2)+3)=0

We multiply parentheses

4a-(7(a-1)-5(a+2)+3)-12=0



We calculate terms in parentheses: -(7(a-1)-5(a+2)+3), so:

7(a-1)-5(a+2)+3

We multiply parentheses

7a-5a-7-10+3

We add all the numbers together, and all the variables

2a-14

Back to the equation:

-(2a-14)



We get rid of parentheses

4a-2a+14-12=0

We add all the numbers together, and all the variables

2a+2=0

We move all terms containing a to the left, all other terms to the right

2a=-2

a=-2/2

a=-1

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