4(2+-5)+3t=40-t

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Solution for 4(2+-5)+3t=40-t equation: 



4(2+-5)+3t=40-t

We move all terms to the left:

4(2+-5)+3t-(40-t)=0

We add all the numbers together, and all the variables

3t-(-1t+40)+4(-3)=0

We add all the numbers together, and all the variables

3t-(-1t+40)-12=0

We get rid of parentheses

3t+1t-40-12=0

We add all the numbers together, and all the variables

4t-52=0

We move all terms containing t to the left, all other terms to the right

4t=52

t=52/4

t=13

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