5-2n=(1/2)(3n-13)

Solution for 5-2n=(1/2)(3n-13) equation:

5-2n=(1/2)(3n-13)

We move all terms to the left:

5-2n-((1/2)(3n-13))=0


Domain of the equation: 2)(3n-13))!=0

n∈R


We add all the numbers together, and all the variables

-2n-((+1/2)(3n-13))+5=0

We multiply parentheses ..

-((+3n^2+1/2*-13))-2n+5=0

We multiply all the terms by the denominator


-((+3n^2+1-2n*2*-13))+5*2*-13))=0


We calculate terms in parentheses: -((+3n^2+1-2n*2*-13)), so:

(+3n^2+1-2n*2*-13)

We get rid of parentheses

3n^2-2n*2*+1-13

We add all the numbers together, and all the variables

3n^2-2n*2*-12

Wy multiply elements

3n^2-4n^2-12

We add all the numbers together, and all the variables

-1n^2-12

Back to the equation:

-(-1n^2-12)


We add all the numbers together, and all the variables

-(-1n^2-12)=0

We get rid of parentheses

1n^2+12=0

We add all the numbers together, and all the variables

n^2+12=0

a = 1; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·1·12
Δ = -48
Delta is less than zero, so there is no solution for the equation