6(2n+1)=2(31-n)

Solution for 6(2n+1)=2(31-n) equation:

6(2n+1)=2(31-n)

We move all terms to the left:

6(2n+1)-(2(31-n))=0

We add all the numbers together, and all the variables

6(2n+1)-(2(-1n+31))=0

We multiply parentheses

12n-(2(-1n+31))+6=0


We calculate terms in parentheses: -(2(-1n+31)), so:

2(-1n+31)

We multiply parentheses

-2n+62

Back to the equation:

-(-2n+62)


We get rid of parentheses

12n+2n-62+6=0

We add all the numbers together, and all the variables

14n-56=0

We move all terms containing n to the left, all other terms to the right

14n=56

n=56/14

n=4