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6x-2x(2+8x)=10+4x
We move all terms to the left:
6x-2x(2+8x)-(10+4x)=0
We add all the numbers together, and all the variables
6x-2x(8x+2)-(4x+10)=0
We multiply parentheses
-16x^2+6x-4x-(4x+10)=0
We get rid of parentheses
-16x^2+6x-4x-4x-10=0
We add all the numbers together, and all the variables
-16x^2-2x-10=0
a = -16; b = -2; c = -10;
Δ = b2-4ac
Δ = -22-4·(-16)·(-10)
Δ = -636
Delta is less than zero, so there is no solution for the equation
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