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5-2(3x-4)=8(2x-1)+10
We move all terms to the left:
5-2(3x-4)-(8(2x-1)+10)=0
We multiply parentheses
-6x-(8(2x-1)+10)+8+5=0
We calculate terms in parentheses: -(8(2x-1)+10), so:We add all the numbers together, and all the variables
8(2x-1)+10
We multiply parentheses
16x-8+10
We add all the numbers together, and all the variables
16x+2
Back to the equation:
-(16x+2)
-6x-(16x+2)+13=0
We get rid of parentheses
-6x-16x-2+13=0
We add all the numbers together, and all the variables
-22x+11=0
We move all terms containing x to the left, all other terms to the right
-22x=-11
x=-11/-22
x=1/2
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