4x-(x-36)=3(x+12)

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Solution for 4x-(x-36)=3(x+12) equation: 



4x-(x-36)=3(x+12)

We move all terms to the left:

4x-(x-36)-(3(x+12))=0

We get rid of parentheses

4x-x-(3(x+12))+36=0



We calculate terms in parentheses: -(3(x+12)), so:

3(x+12)

We multiply parentheses

3x+36

Back to the equation:

-(3x+36)



We add all the numbers together, and all the variables

3x-(3x+36)+36=0

We get rid of parentheses

3x-3x-36+36=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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