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1(2x)=(2(1x-8)+3
We move all terms to the left:
1(2x)-((2(1x-8)+3)=0
We add all the numbers together, and all the variables
12x-((2(x-8)+3)=0
We calculate terms in parentheses: -((2(x-8)+3), so:
(2(x-8)+3
We calculate terms in parentheses: -((2(x-8)+3), so:
(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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(2(x-8)+3
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