9+2(y-3)=3(y-2)+1

Solution for 9+2(y-3)=3(y-2)+1 equation:

9+2(y-3)=3(y-2)+1

We move all terms to the left:

9+2(y-3)-(3(y-2)+1)=0

We multiply parentheses

2y-(3(y-2)+1)-6+9=0


We calculate terms in parentheses: -(3(y-2)+1), so:

3(y-2)+1

We multiply parentheses

3y-6+1

We add all the numbers together, and all the variables

3y-5

Back to the equation:

-(3y-5)


We add all the numbers together, and all the variables

2y-(3y-5)+3=0

We get rid of parentheses

2y-3y+5+3=0

We add all the numbers together, and all the variables

-1y+8=0

We move all terms containing y to the left, all other terms to the right

-y=-8

y=-8/-1

y=+8