5-(x-2)+3x=10x-3(4x-5)

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Solution for 5-(x-2)+3x=10x-3(4x-5) equation: 



5-(x-2)+3x=10x-3(4x-5)

We move all terms to the left:

5-(x-2)+3x-(10x-3(4x-5))=0

We add all the numbers together, and all the variables

3x-(x-2)-(10x-3(4x-5))+5=0

We get rid of parentheses

3x-x-(10x-3(4x-5))+2+5=0



We calculate terms in parentheses: -(10x-3(4x-5)), so:

10x-3(4x-5)

We multiply parentheses

10x-12x+15

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We add all the numbers together, and all the variables

2x-(-2x+15)+7=0

We get rid of parentheses

2x+2x-15+7=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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