7x2+8x+1=0

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Solution for 7x2+8x+1=0 equation: 



7x^2+8x+1=0

a = 7; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·7·1
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-6}{2*7}=\frac{-14}{14}
=-1
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+6}{2*7}=\frac{-2}{14}
=-1/7
$

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