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5+5=10x^2
We move all terms to the left:
5+5-(10x^2)=0
We add all the numbers together, and all the variables
-10x^2+10=0
a = -10; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-10)·10
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-10}=\frac{-20}{-20} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-10}=\frac{20}{-20} =-1 $
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