5(r-3)-4(r-1)=2(r+6)

Solution for 5(r-3)-4(r-1)=2(r+6) equation:

5(r-3)-4(r-1)=2(r+6)

We move all terms to the left:

5(r-3)-4(r-1)-(2(r+6))=0

We multiply parentheses

5r-4r-(2(r+6))-15+4=0


We calculate terms in parentheses: -(2(r+6)), so:

2(r+6)

We multiply parentheses

2r+12

Back to the equation:

-(2r+12)


We add all the numbers together, and all the variables

r-(2r+12)-11=0

We get rid of parentheses

r-2r-12-11=0

We add all the numbers together, and all the variables

-1r-23=0

We move all terms containing r to the left, all other terms to the right

-r=23

r=23/-1

r=-23