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5+2(x-4)=3(x-5)-5x
We move all terms to the left:
5+2(x-4)-(3(x-5)-5x)=0
We multiply parentheses
2x-(3(x-5)-5x)-8+5=0
We calculate terms in parentheses: -(3(x-5)-5x), so:We add all the numbers together, and all the variables
3(x-5)-5x
We add all the numbers together, and all the variables
-5x+3(x-5)
We multiply parentheses
-5x+3x-15
We add all the numbers together, and all the variables
-2x-15
Back to the equation:
-(-2x-15)
2x-(-2x-15)-3=0
We get rid of parentheses
2x+2x+15-3=0
We add all the numbers together, and all the variables
4x+12=0
We move all terms containing x to the left, all other terms to the right
4x=-12
x=-12/4
x=-3
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