7(2x-3)-6(x-2)-2(5x+6)-3(6x-5)=-4(3x-4)+26

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Solution for 7(2x-3)-6(x-2)-2(5x+6)-3(6x-5)=-4(3x-4)+26 equation: 



7(2x-3)-6(x-2)-2(5x+6)-3(6x-5)=-4(3x-4)+26

We move all terms to the left:

7(2x-3)-6(x-2)-2(5x+6)-3(6x-5)-(-4(3x-4)+26)=0

We multiply parentheses

14x-6x-10x-18x-(-4(3x-4)+26)-21+12-12+15=0



We calculate terms in parentheses: -(-4(3x-4)+26), so:

-4(3x-4)+26

We multiply parentheses

-12x+16+26

We add all the numbers together, and all the variables

-12x+42

Back to the equation:

-(-12x+42)



We add all the numbers together, and all the variables

-20x-(-12x+42)-6=0

We get rid of parentheses

-20x+12x-42-6=0

We add all the numbers together, and all the variables

-8x-48=0

We move all terms containing x to the left, all other terms to the right

-8x=48

x=48/-8

x=-6

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