3(2-x)+5=4-2(x+1)

Solution for 3(2-x)+5=4-2(x+1) equation:

3(2-x)+5=4-2(x+1)

We move all terms to the left:

3(2-x)+5-(4-2(x+1))=0

We add all the numbers together, and all the variables

3(-1x+2)-(4-2(x+1))+5=0

We multiply parentheses

-3x-(4-2(x+1))+6+5=0


We calculate terms in parentheses: -(4-2(x+1)), so:

4-2(x+1)

determiningTheFunctionDomain
-2(x+1)+4

We multiply parentheses

-2x-2+4

We add all the numbers together, and all the variables

-2x+2

Back to the equation:

-(-2x+2)


We add all the numbers together, and all the variables

-3x-(-2x+2)+11=0

We get rid of parentheses

-3x+2x-2+11=0

We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9