5(y-2)=9y+6-2(-5y-1)

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Solution for 5(y-2)=9y+6-2(-5y-1) equation: 



5(y-2)=9y+6-2(-5y-1)

We move all terms to the left:

5(y-2)-(9y+6-2(-5y-1))=0

We multiply parentheses

5y-(9y+6-2(-5y-1))-10=0



We calculate terms in parentheses: -(9y+6-2(-5y-1)), so:

9y+6-2(-5y-1)

determiningTheFunctionDomain
9y-2(-5y-1)+6

We multiply parentheses

9y+10y+2+6

We add all the numbers together, and all the variables

19y+8

Back to the equation:

-(19y+8)



We get rid of parentheses

5y-19y-8-10=0

We add all the numbers together, and all the variables

-14y-18=0

We move all terms containing y to the left, all other terms to the right

-14y=18

y=18/-14

y=-1+2/7

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