7n+32=7n-2(n-2)

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Solution for 7n+32=7n-2(n-2) equation: 



7n+32=7n-2(n-2)

We move all terms to the left:

7n+32-(7n-2(n-2))=0



We calculate terms in parentheses: -(7n-2(n-2)), so:

7n-2(n-2)

We multiply parentheses

7n-2n+4

We add all the numbers together, and all the variables

5n+4

Back to the equation:

-(5n+4)



We get rid of parentheses

7n-5n-4+32=0

We add all the numbers together, and all the variables

2n+28=0

We move all terms containing n to the left, all other terms to the right

2n=-28

n=-28/2

n=-14

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