-2(3x-4)+7x=2+4(4x-1)

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Solution for -2(3x-4)+7x=2+4(4x-1) equation: 



-2(3x-4)+7x=2+4(4x-1)

We move all terms to the left:

-2(3x-4)+7x-(2+4(4x-1))=0

We add all the numbers together, and all the variables

7x-2(3x-4)-(2+4(4x-1))=0

We multiply parentheses

7x-6x-(2+4(4x-1))+8=0



We calculate terms in parentheses: -(2+4(4x-1)), so:

2+4(4x-1)

determiningTheFunctionDomain
4(4x-1)+2

We multiply parentheses

16x-4+2

We add all the numbers together, and all the variables

16x-2

Back to the equation:

-(16x-2)



We add all the numbers together, and all the variables

x-(16x-2)+8=0

We get rid of parentheses

x-16x+2+8=0

We add all the numbers together, and all the variables

-15x+10=0

We move all terms containing x to the left, all other terms to the right

-15x=-10

x=-10/-15

x=2/3

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