5(y-1)+20=4(y-3)

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Solution for 5(y-1)+20=4(y-3) equation: 



5(y-1)+20=4(y-3)

We move all terms to the left:

5(y-1)+20-(4(y-3))=0

We multiply parentheses

5y-(4(y-3))-5+20=0



We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We add all the numbers together, and all the variables

5y-(4y-12)+15=0

We get rid of parentheses

5y-4y+12+15=0

We add all the numbers together, and all the variables

y+27=0

We move all terms containing y to the left, all other terms to the right

y=-27

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