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1+2x-(3x-(4x-5))=11x+2
We move all terms to the left:
1+2x-(3x-(4x-5))-(11x+2)=0
We get rid of parentheses
2x-(3x-(4x-5))-11x-2+1=0
We calculate terms in parentheses: -(3x-(4x-5)), so:We add all the numbers together, and all the variables
3x-(4x-5)
We get rid of parentheses
3x-4x+5
We add all the numbers together, and all the variables
-1x+5
Back to the equation:
-(-1x+5)
-9x-(-1x+5)-1=0
We get rid of parentheses
-9x+1x-5-1=0
We add all the numbers together, and all the variables
-8x-6=0
We move all terms containing x to the left, all other terms to the right
-8x=6
x=6/-8
x=-3/4
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