3(2r+1)+7(6r-1)=5(12r-7)+23

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Solution for 3(2r+1)+7(6r-1)=5(12r-7)+23 equation: 



3(2r+1)+7(6r-1)=5(12r-7)+23

We move all terms to the left:

3(2r+1)+7(6r-1)-(5(12r-7)+23)=0

We multiply parentheses

6r+42r-(5(12r-7)+23)+3-7=0



We calculate terms in parentheses: -(5(12r-7)+23), so:

5(12r-7)+23

We multiply parentheses

60r-35+23

We add all the numbers together, and all the variables

60r-12

Back to the equation:

-(60r-12)



We add all the numbers together, and all the variables

48r-(60r-12)-4=0

We get rid of parentheses

48r-60r+12-4=0

We add all the numbers together, and all the variables

-12r+8=0

We move all terms containing r to the left, all other terms to the right

-12r=-8

r=-8/-12

r=2/3

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