5(y+3)=-3(6y-4)+8y

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Solution for 5(y+3)=-3(6y-4)+8y equation:



5(y+3)=-3(6y-4)+8y
We move all terms to the left:
5(y+3)-(-3(6y-4)+8y)=0
We multiply parentheses
5y-(-3(6y-4)+8y)+15=0
We calculate terms in parentheses: -(-3(6y-4)+8y), so:
-3(6y-4)+8y
We add all the numbers together, and all the variables
8y-3(6y-4)
We multiply parentheses
8y-18y+12
We add all the numbers together, and all the variables
-10y+12
Back to the equation:
-(-10y+12)
We get rid of parentheses
5y+10y-12+15=0
We add all the numbers together, and all the variables
15y+3=0
We move all terms containing y to the left, all other terms to the right
15y=-3
y=-3/15
y=-1/5

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