8+2(2v-9)=-5(2v-1)+8v

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Solution for 8+2(2v-9)=-5(2v-1)+8v equation:



8+2(2v-9)=-5(2v-1)+8v
We move all terms to the left:
8+2(2v-9)-(-5(2v-1)+8v)=0
We multiply parentheses
4v-(-5(2v-1)+8v)-18+8=0
We calculate terms in parentheses: -(-5(2v-1)+8v), so:
-5(2v-1)+8v
We add all the numbers together, and all the variables
8v-5(2v-1)
We multiply parentheses
8v-10v+5
We add all the numbers together, and all the variables
-2v+5
Back to the equation:
-(-2v+5)
We add all the numbers together, and all the variables
4v-(-2v+5)-10=0
We get rid of parentheses
4v+2v-5-10=0
We add all the numbers together, and all the variables
6v-15=0
We move all terms containing v to the left, all other terms to the right
6v=15
v=15/6
v=2+1/2

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